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DropletMVP

Poisson single-cell loading

Probability that a droplet contains 0, exactly 1, or 2+ cells during encapsulation.

Inputs

Model assumptions

Cells are assumed independent and randomly distributed (Poisson statistics). To keep doublets rare you must run at low λ — which means most droplets are empty. There is no λ that gives mostly single-cell droplets.
cells/droplet

λ = cell concentration × droplet volume. Typical scRNA-seq: λ ≈ 0.1.

Result

Enter λ and calculate to see the occupancy distribution.

Interpretation

Single-cell platforms run at low λ so that among occupied droplets, very few contain two or more cells. The cost is that most droplets end up empty.

Formula

Poisson probability of k cells
P(k) = λᵏ · e^(−λ) / k!

λ is the mean number of cells per droplet.

Variables

SymbolVariableUnit
P(k)Probability of k cells in a droplet—
λMean cells per droplet—
kNumber of cells—

Assumptions & validity

Worked example

At λ = 0.1 cells per droplet:

P(0) = e⁻⁰·¹ ≈ 90.5% · P(1) = 0.1·e⁻⁰·¹ ≈ 9.0% · P(2+) ≈ 0.5%

Doublets are ~0.5% — but ~90% of droplets are wasted as empties.