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Device physicsMVP

Parallel-plate capacitor

Capacitance of an ideal parallel-plate capacitor from plate area, spacing, and dielectric.

Inputs

e.g. 1 (vacuum), 3.9 (SiO₂), ~3.9–25 (various dielectrics).

Result

Enter values and calculate to see the result.

Interpretation

Enter the plate area, spacing, and dielectric constant.

Formula

Parallel-plate capacitor
C = ε₀ · εr · A / d

ε₀ = vacuum permittivity.

Variables

SymbolVariableUnit
CCapacitanceF (shown as pF/nF)
ε₀Vacuum permittivityF/m (8.854×10⁻¹²)
εrRelative permittivitydimensionless
APlate aream²
dPlate spacingm

Assumptions & validity

Worked example

A = 1 mm², d = 100 nm, εr = 3.9 (SiO₂).

C = ε₀·3.9·1e-6/1e-7 ≈ 345 pF